Many thanks.

On Jun 16, 12:18 pm, David Santiago <david.santi...@gmail.com> wrote:
> Change the first line to something like (def csv (parse-csv (slurp
> "path/to/my/file.csv"))).
>
>   -  David
>
> On Thu, Jun 16, 2011 at 8:20 AM, octopusgrabbus
>
>
>
>
>
>
>
> <octopusgrab...@gmail.com> wrote:
> > I would like to modify the examples given
>
> > user=> (def csv (parse-csv "1,2,3\n4,5,6\n7,8,9"))
> > #'user/csv
> > user=> (nth (nth csv 1) 2)  ;; Get 2nd row, last column.
> > "6"
> > user=> (-> csv (nth 1) (nth 2))  ;; Another way to do it.
> > "6"
> > user=> (defn get-column [parsed-csv col] (map #(nth % col)
> > parsed-csv)) ;; Function to return a given column.
> > #'user/get-column
> > user=> (get-column csv 1) ;; Get second column as a sequence.
> > ("2" "5" "8")
>
> > to read in a .csv file, and then perform the functions on the parsed
> > csv file, but I am getting clojure.lang.LazySeq cannot be cast to
> > clojure.lang.IFn.
>
> > How do I do this properly?
> > Thanks.
>
> > On Jun 16, 12:20 am, David Santiago <david.santi...@gmail.com> wrote:
> >> Here's a repl session that will hopefully demonstrate how to do a few
> >> things, including pull out an entire column. Just remember the library
> >> turns CSVs into regular clojure data structures, so getting the data
> >> you want out of the return value of the parse is just about indexing
> >> into vectors.
>
> >> user=> (use 'clojure-csv.core)
> >> nil
> >> user=> (def csv (parse-csv "1,2,3\n4,5,6\n7,8,9"))
> >> #'user/csv
> >> user=> (nth (nth csv 1) 2)  ;; Get 2nd row, last column.
> >> "6"
> >> user=> (-> csv (nth 1) (nth 2))  ;; Another way to do it.
> >> "6"
> >> user=> (defn get-column [parsed-csv col] (map #(nth % col)
> >> parsed-csv)) ;; Function to return a given column.
> >> #'user/get-column
> >> user=> (get-column csv 1) ;; Get second column as a sequence.
> >> ("2" "5" "8")
>
> >>   - David
>
> >> On Wed, Jun 15, 2011 at 9:58 PM, octopusgrabbus
>
> >> <octopusgrab...@gmail.com> wrote:
> >> > I've got to go back and look at your documentation. I'm not sure how
> >> > to pull the columns out of each row.
>
> >> > On Jun 15, 5:04 pm, David Santiago <david.santi...@gmail.com> wrote:
> >> >> I'm afraid I don't understand the question. What do you mean
> >> >> "positionally?" When it parses the CSV file, it gives you back a
> >> >> stream of rows, each row being a vector of the contents of each cell
> >> >> of the CSV. If you are interested in cells at a given row/column, you
> >> >> should be able to count into those vectors fairly naturally...
>
> >> >>    - David
>
> >> >> On Wed, Jun 15, 2011 at 2:08 PM, 
> >> >> octopusgrabbus<octopusgrab...@gmail.com> wrote:
> >> >> > Is it possible to use clojure-csv to extract data positionally in
> >> >> > a .csv file, or should I use BufferedReader to read each line lazily
> >> >> > and apply splitting the line up into fields by delimiter?
>
> >> >> > Thanks.
> >> >> > cmn
>
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