On Tue, Mar 4, 2008 at 11:18 PM, yitzle <[EMAIL PROTECTED]> wrote:
> On Tue, Mar 4, 2008 at 10:35 PM, Chas. Owens <[EMAIL PROTECTED]> wrote:
> > A terminal that can handle UTF-8.
> >
> > You may need to put this in your profile
> > #fix UTF-8 support
> > export LC_CTYPE=en_US.UTF-8 #vim ne
On Tue, Mar 4, 2008 at 10:35 PM, Chas. Owens <[EMAIL PROTECTED]> wrote:
> A terminal that can handle UTF-8.
>
> You may need to put this in your profile
> #fix UTF-8 support
> export LC_CTYPE=en_US.UTF-8 #vim needs this to swtich it from Latin1 to UTF-8
> export PERL_UNICODE=SDL #Makes Per
On Tue, Mar 4, 2008 at 10:23 PM, yitzle <[EMAIL PROTECTED]> wrote:
> On Tue, Mar 4, 2008 at 8:29 PM, Chas. Owens <[EMAIL PROTECTED]> wrote:
> > Nope, due to addition of Unicode support in recent versions of Perl it
> > will also match "\x{1814}" the Mongolian digit 4. The \d character
> > cl
On Tue, Mar 4, 2008 at 8:29 PM, Chas. Owens <[EMAIL PROTECTED]> wrote:
> Nope, due to addition of Unicode support in recent versions of Perl it
> will also match "\x{1814}" the Mongolian digit 4. The \d character
> class is not the same as [0-9], it matches all number characters,
> including t
On Tue, Mar 4, 2008 at 8:06 PM, MK <[EMAIL PROTECTED]> wrote:
> On 03/04/2008 03:41:44 PM, yitzle wrote:
>
> -> I'd use a RegEx and test to see if the string is made up entirely of
>
> -> integers.
> -> print "The variable containing $p is an interger\n" if ($p =~
> -> /^[0-9]+$/);
>
> yitzle
On 03/04/2008 03:41:44 PM, yitzle wrote:
-> I'd use a RegEx and test to see if the string is made up entirely of
-> integers.
-> print "The variable containing $p is an interger\n" if ($p =~
-> /^[0-9]+$/);
yitzle would seem to have the most foolproof solution. The only
problem would be if
[EMAIL PROTECTED] schreef:
> How to find out the specific variable contains integer value. In my
> script ,variable is storing some value but I want to find out whether
> that value is string or integer.
In Perl, data types are like scalar, array, hash. Operator types are
like numeric, string.
$
Andrew has got a good point. The perldoc page says:
if (/^\d+$/) { print "is a whole number\n" }
which would indicate that the author of the perldoc page believes
"123\n" should classify as a number, while "123foo" shouldn't, even
though Perl sometimes treats "123foo" as a number.
I was going to
"perl pra" schreef:
> I wanted to validate xml file against specified xsd file.
> Is there any perl module which does this?
Try XML::Compile
"The schema is not strictly validated. In many cases, compile-time
errors will get reported. On the other hand, the processed data is
strictly validated ag
On Mon, Mar 3, 2008 at 5:32 PM, David Newman <[EMAIL PROTECTED]> wrote:
> Greetings. I'm looking to compare two contact lists in csv format, and
> then print out "here are the records in in Llist only, in Rlist only,
> and what's in common."
>
> I should compare only 3 of the 82 fields in each l
On Tue, Mar 4, 2008 at 4:44 PM, Randal L. Schwartz
<[EMAIL PROTECTED]> wrote:
> > ""Andrew" == "Andrew Curry" <[EMAIL PROTECTED]> writes:
>
> "Andrew> If you are not 100% sure then you can also do if ($x =~/^\d*$/) for
> an
> "Andrew> actual integer i.e. a number in the positive whole set of
True enough however please don't be so rude, people should be free to
post the answers they think if only to be corrected and learn, and not
be scared off by know by flippant replies.
You are correct it will return a false positive as will $x=~/^[0-9]*$/
for that matter. But its an ultra simple so
> "Chas" == Chas Owens <[EMAIL PROTECTED]> writes:
Chas> I cannot disagree with this sentiment more. Bad answers offer the
Chas> chance to teach more than one person at a time. People should not be
Chas> afraid to post answers to this list; however, it is a good idea to
Chas> test your answe
On Tue, Mar 4, 2008 at 4:43 PM, Randal L. Schwartz
<[EMAIL PROTECTED]> wrote:
snip
> And you might want to note that submitting a *bad* answer to the beginners
> mailing list is worse than submitting *no* answer, because it means that the
> resources of People With More Experience Than You now h
> ""Andrew" == "Andrew Curry" <[EMAIL PROTECTED]> writes:
"Andrew> If you are not 100% sure then you can also do if ($x =~/^\d*$/) for an
"Andrew> actual integer i.e. a number in the positive whole set of numbers {
"Andrew> 1,2,3} or negative whole numbers -1,-2,-3 or 0.
This also f
> ""Rodrick" == "Rodrick Brown" <[EMAIL PROTECTED]> writes:
"Rodrick> #!/usr/bin/perl
"Rodrick> my $p = 10;
"Rodrick> if( int($p) ) {
"Rodrick> print "$p is an interger\n";
"Rodrick> }
"Rodrick> ~
Not even close.
$ perldoc -f int
int EXPR
int Returns the integer portion of EXP
Correction its not that it's a string (which it is) its that int doesn't
like 0 even thought it's an integer by definition.
-Original Message-
From: Andrew Curry [mailto:[EMAIL PROTECTED]
Sent: 04 March 2008 20:52
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Cc: beginners@perl.org
Subject: RE
Be warned though that int isn't cleaver enough to deal with say...
$x='0';
print int($x);
still says it's a string as It is.
If you are not 100% sure then you can also do if ($x =~/^\d*$/) for an
actual integer i.e. a number in the positive whole set of numbers {
1,2,3} or negative whole nu
[EMAIL PROTECTED] wrote:
Hi All,
Hello,
How to find out the specific variable contains integer value. In my
script ,variable is storing some value but I want to find out whether
that value is string or integer.
perldoc -q integer
Also look for the function looks_like_number() in:
perldoc
Thanks.
Can you please explain the reg. expression in more detail.
Please
--Irfan.
Project Lead
TSINDIA - Production Line
Individual Software Solutions - UMO
T-Systems India Private Limited, Pune
Telephone: +91-20-30245000/25605000 (Extn: 5271)
Mobile: +91 9822 854 227
Fax: ++91-020 25674090
Thanks Brown. It worked.
-Original Message-
From: Rodrick Brown [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 05, 2008 1:50 AM
To: Sayed, Irfan
Cc: beginners@perl.org
Subject: Re: variable help
#!/usr/bin/perl
my $p = 10;
if( int($p) ) {
print "$p is an interger\n";
}
~
On Tue,
This approach does not consider "0" to be an integer.
I'd use a RegEx and test to see if the string is made up entirely of integers.
print "The variable containing $p is an interger\n" if ($p =~ /^[0-9]+$/);
On Tue, Mar 4, 2008 at 3:19 PM, Rodrick Brown <[EMAIL PROTECTED]> wrote:
> #!/usr/bin/pe
#!/usr/bin/perl
my $p = 10;
if( int($p) ) {
print "$p is an interger\n";
}
~
On Tue, Mar 4, 2008 at 3:16 PM, <[EMAIL PROTECTED]> wrote:
> Hi All,
>
>
>
> How to find out the specific variable contains integer value. In my
> script ,variable is storing some value but I want to find out whethe
Hi All,
How to find out the specific variable contains integer value. In my
script ,variable is storing some value but I want to find out whether
that value is string or integer.
Please help
Regards
Irfan.
(Randal L. Schwartz) wrote:
"Gunnar" == Gunnar Hjalmarsson <[EMAIL PROTECTED]> writes:
Gunnar> my ($comp) = /([^,]*,[^,]*,[^,]*)/;
Gunnar> $Llist{$comp} = $_;
These lines scare me. What happens if the regex fails?
And if you never expect it to fail, at least add a "die", to p
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