Correction its not that it's a string (which it is) its that int doesn't
like 0 even thought it's an integer by definition.

-----Original Message-----
From: Andrew Curry [mailto:[EMAIL PROTECTED] 
Sent: 04 March 2008 20:52
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Cc: beginners@perl.org
Subject: RE: variable help

Be warned though that int isn't cleaver enough to deal with say...

$x='0';
print int($x);

still says it's a string as It is.

If you are not 100% sure then you can also do if ($x =~/^\d*$/) for an
actual integer i.e. a number in the positive whole set of numbers {
1,2,3....}  or negative whole numbers -1,-2,-3.... or 0. 

-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] 
Sent: 04 March 2008 20:42
To: [EMAIL PROTECTED]
Cc: beginners@perl.org
Subject: RE: variable help

Thanks Brown. It worked.


-----Original Message-----
From: Rodrick Brown [mailto:[EMAIL PROTECTED] 
Sent: Wednesday, March 05, 2008 1:50 AM
To: Sayed, Irfan
Cc: beginners@perl.org
Subject: Re: variable help

#!/usr/bin/perl

my $p = 10;

if( int($p) ) {
  print "$p is an interger\n";
}
~


On Tue, Mar 4, 2008 at 3:16 PM,  <[EMAIL PROTECTED]> wrote:
> Hi All,
>
>
>
> How to find out the specific variable contains integer value. In my
> script ,variable is storing some value but I want to find out whether
> that value is string or integer.
>
>
>
> Please help
>
>
>
> Regards
>
> Irfan.
>
>



-- 
Rodrick R. Brown
http://www.rodrickbrown.com
http://www.linkedin.com/in/rodrickbrown

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