Be warned though that int isn't cleaver enough to deal with say...
$x='0';
print int($x);
still says it's a string as It is.
If you are not 100% sure then you can also do if ($x =~/^\d*$/) for an
actual integer i.e. a number in the positive whole set of numbers {
1,2,3....} or negative whole numbers -1,-2,-3.... or 0.
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: 04 March 2008 20:42
To: [EMAIL PROTECTED]
Cc: beginners@perl.org
Subject: RE: variable help
Thanks Brown. It worked.
-----Original Message-----
From: Rodrick Brown [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 05, 2008 1:50 AM
To: Sayed, Irfan
Cc: beginners@perl.org
Subject: Re: variable help
#!/usr/bin/perl
my $p = 10;
if( int($p) ) {
print "$p is an interger\n";
}
~
On Tue, Mar 4, 2008 at 3:16 PM, <[EMAIL PROTECTED]> wrote:
> Hi All,
>
>
>
> How to find out the specific variable contains integer value. In my
> script ,variable is storing some value but I want to find out whether
> that value is string or integer.
>
>
>
> Please help
>
>
>
> Regards
>
> Irfan.
>
>
--
Rodrick R. Brown
http://www.rodrickbrown.com
http://www.linkedin.com/in/rodrickbrown
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