Nothing I know of, but if they are not arriving parallel to the axis, they
will not pass through the focal point (which is where the feed is).
Remember tha angle of incidence = angle of reflection, so for any given
point, if you know the angle which it arrived in reference to the point at
which it
Maybe he's trying to block out a multipath reflected or ducted signal. I think
this is difficult or impossible because1) the angular difference is too small2)
the shield is too close to the antenna3) knife edge diffraction Original
Message From: "Cameron Crum" Sent: 8/14/2024 9:33:48 AMT
If it comes in off axis, it will appear on the opposite side of the focal
point. You can actually move the feed horn around quite a bit and compensate
for it by re aiming the reflector. Minor loss of gain, more loss the more you
deviate from boresight.
And the actual boresight focal point
So he's not trying to implement something like horse blinders? Original
Message From: chuck@go-mtc.comSent: 8/14/2024 10:44:06 AMTo: "AnimalFarm
Microwave Users Group" Subject: Re: [AFMUG] parabolic shield calculator
If it comes in off axis, it will appear on the opposite side of the f
You can always add a shroud to all parabolic reflectors to eliminate sidelobes.
From: Ken Hohhof
Sent: Wednesday, August 14, 2024 10:54 AM
To: af@af.afmug.com
Subject: Re: [AFMUG] parabolic shield calculator
So he's not trying to implement something like horse blinders?
Original Messa
