date:20130610

Re: Changing filenames from Greeklish => Greek (subprocess complain)

2013-06-10 Thread nagia . retsina

Τη Κυριακή, 9 Ιουνίου 2013 3:31:44 μ.μ. UTC+3, ο χρήστης Steven D'Aprano έγραψε:

> py> c = 'α'
> py> ord(c)
> 945

The number 945 is the characters 'α' ordinal value in the unicode charset 
correct?

The command in the python interactive session to show me how many bytes
this character will take upon encoding to utf-8 is:

>>> s = 'α'
>>> s.encode('utf-8')
b'\xce\xb1'

I see that the encoding of this char takes 2 bytes. But why two exactly?
How do i calculate how many bits are needed to store this char into bytes?


Trying to to the same here but it gave me no bytes back.

>>> s = 'a'
>>> s.encode('utf-8')
b'a'


>py> c.encode('utf-8')
> b'\xce\xb1'

2 bytes here. why 2?

> py> c.encode('utf-16be')
> b'\x03\xb1'

2 byets here also. but why 3 different bytes? the ordinal value of char 'a' is 
the same in unicode. the encodign system just takes the ordinal value end 
encode, but sinc eit uses 2 bytes should these 2 bytes be the same?

> py> c.encode('utf-32be')
> b'\x00\x00\x03\xb1

every char here takes exactly 4 bytes to be stored. okey.

> py> c.encode('iso-8859-7')
> b'\xe1'

And also does '\x' means that the value is being respresented in hex way?
and when i bin(6) i see '0b101'

I should expect to see 8 bits of 1s and 0's. what the 'b' is tryign to say?
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Re: Re-using copyrighted code

2013-06-10 Thread Chris Angelico

On Mon, Jun 10, 2013 at 4:42 PM, Malte Forkel  wrote:
> Had I known in the beginning how convoluted things would become, I might
> have considered two other options: Just publish or keep the code to
> myself.  But I still think, first understanding the legal aspects and
> then publishing (to give back at least a little) is the way to go.
>
> I certainly hope that there is no software out thre that didn't get
> released to the public because its author found the legal implications
> to difficult to handle.

Understanding is good :)

Unfortunately there will be heaps of software that didn't get released
owing to potential legal messes. It's a loss that could be partially
avoided in future by authors sticking to the well-known licenses; it's
easy to make a derivative work based on three or four different
components if they all use the same license. I've seen issues all over
the place stemming from GNU Readline (which is GPL, not LGPL) and
something not GPL-compat being both linked to the same application;
and it's so likely as to be practically certain that there have been
things left unreleased because of that.

ChrisA
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Re: Re-using copyrighted code

2013-06-10 Thread Mark Janssen

>>> Can you provide any citations for your interpretation? Besides "that's
>>> what the law should be", I mean.
>>
>> I don't think I even have to:  the legal code you're citing above is
>> not very clear, consistent, or well-defined at all.  As such, it shows
>> that this area remains an area that has yet to be worked out by all
>> parties involved.   I would happily volunteer for any interested
>> parties to such a broken system.  Alternatively, I've been working on
>> a real fix to IP protections in the form of a unified data model for
>> the internet and data ecosystem.
>
> Except that's now how law works in the US.  All laws are unclear,
> inconsistent or ill-defined.

Yes, but the issue is that some participants were suggesting that the
law *is* clear when it is not -- so what is the procedure to follow
when that is the case?

>Many laws even contradict existing laws.
> That's why there's a long history and tradition (for good or ill) of
> courts establishing case law to clarify and codify the implementation of
> law, and to resolve incompatibilities and consistencies.
>
> So while your views may be logical to you, and even common sense, unless
> case law backs you up, your opinions are irrelevant to the actual
> implementation of copyright law.

No, the system of law is made for, and by the people, so while it may
not reflect consensus, it isn't necessarily irrelevant and in any case
where there are people spouting law as if it WAS clear, someone must
do the job breaking down the walls.

> As much as many of us are open source or even free software advocates,
> we do have to live within the copyright law currently,

We do not have to live within it, we can create it.  Where did you get
this idea?

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MarkJ
Tacoma, Washington
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Re: problem with if then

2013-06-10 Thread Jean Dubois

On 9 jun, 23:35, Roy Smith  wrote:
> In article
> <20165c85-4cc3-4b79-943b-82443e4a9...@w7g2000vbw.googlegroups.com>,
>  Jean Dubois  wrote:
>
> > But, really,
> > > once you've done all that (and it's worth doing as an exercise), rewrite
> > > your code to use urllib2 or requests.  It'll be a lot easier.
>
> > Could you show me how to code the  example in metacode below wuth the
> > use of urllib2?
> > #!/usr/bin/env python
> > import urllib2
> > if check whether url exists succeed:
> >     print 'url exists'
> > else:
> >     print 'url does not exist'
>
> There are two basic ways Python function return status information.
> Either they return something which indicates failure (such as None), or
> they raise an exception.
>
> In this case, what you want is urlopen(), which is documented 
> athttp://docs.python.org/2/library/urllib2.html.  The key piece of
> information is a couple of paragraphs down, where it says, "Raises
> URLError on errors".
>
> It's not obvious from reading that whether URLError is a built-in or
> not, but that's easy enough to figure out:
>
> >>> URLError
>
> Traceback (most recent call last):
>   File "", line 1, in 
> NameError: name 'URLError' is not defined>>> import urllib2
> >>> urllib2.URLError
>
> 
>
> So, that means you want something like:
>
> #!/usr/bin/env python
>
> import urllib2
>
> url = "http://whatever";
> try:
>    urllib2.urlopen(url)
>    print "url exists"
> except urllib2.URLError:
>    print "url does not exist"

thanks a lot, this works like a charm

jean
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Re: Changing filenames from Greeklish => Greek (subprocess complain)

2013-06-10 Thread Larry Hudson

On 06/09/2013 03:37 AM, Νικόλαος Κούρας wrote:

I mean utf-8 could use 1 byte for storing the 1st 256 characters. I meant up to
256, not above 256.

NO!!

0 - 127, yes.
128 - 255 -> one byte of a multibyte code.

That's why the decode fails, it sees it as incomplete data so it can't do
anything with it.

A surrogate pair is like itting for example Ctrl-A, which means is a
combination character that consists of 2 different characters?
Is this what a surrogate is? a pari of 2 chars?

You're confusing character encodings with the way NON-CHARACTER keys on the KEYBOARD are encoded
(function keys, arrow keys and such). These are NOT text characters but KEYBOARD key codes.
These are NOT text codes and are entirely different and not related to any character encoding.
How programs interpret and use these codes depends entirely on the individual programs. There
are common conventions on how many are used, but there are no standards.

Also the control-codes are the first 32 values of the ASCII (and ASCII-compatible) character set
and are not multi-character key codes like the keyboard non-character keys.

However, there are a few keyboard keys that actually produce control-codes. A
few examples:

Return/Enter -> Ctrl-M
Tab -> Ctrl-I
Backspace -> Ctrl-H

So character 'A' <-> 65 (in decimal uses in charset's table) <-> 01011100 (as binary
stored in disk) <-> 0xEF (as hex, when we open the file with a hex editor)

You are trying to put too much meaning to this. The value stored on disk, in memory, or
whatever is binary bits, nothing else. How you describe the value, in decimal, in octal, in
hex, in base-12, or... is totally irrelevant. These are simply different ways of describing or
naming these numeric values.

It's the same as saying 3 in English is three, in Spanish is tres, in German is drei... (I
don't know Greek, sorry.) No matter what you call it, it is still the numeric integer value
that is between 2 and 4.

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