Τη Δευτέρα, 10 Ιουνίου 2013 10:51:34 π.μ. UTC+3, ο χρήστης Larry Hudson έγραψε:

> > I mean utf-8 could use 1 byte for storing the 1st 256 characters. I meant 
> > up to 256, not above 256.

> 0 - 127, yes.
> 128 - 255 -> one byte of a multibyte code.

you mean that in utf-8 for 1 character to be stored, we need 2 bytes?
I still havign troubl e understanding this.

Since 2^8 = 256, utf-8 would need 1 byte to store the 1st 256 characters but 
instead its using 1 byte up to the first 127 value and then 2 bytes for 
anyhtign above.  Why?
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