On 9 jun, 23:35, Roy Smith <r...@panix.com> wrote: > In article > <20165c85-4cc3-4b79-943b-82443e4a9...@w7g2000vbw.googlegroups.com>, > Jean Dubois <jeandubois...@gmail.com> wrote: > > > But, really, > > > once you've done all that (and it's worth doing as an exercise), rewrite > > > your code to use urllib2 or requests. It'll be a lot easier. > > > Could you show me how to code the example in metacode below wuth the > > use of urllib2? > > #!/usr/bin/env python > > import urllib2 > > if check whether url exists succeed: > > print 'url exists' > > else: > > print 'url does not exist' > > There are two basic ways Python function return status information. > Either they return something which indicates failure (such as None), or > they raise an exception. > > In this case, what you want is urlopen(), which is documented > athttp://docs.python.org/2/library/urllib2.html. The key piece of > information is a couple of paragraphs down, where it says, "Raises > URLError on errors". > > It's not obvious from reading that whether URLError is a built-in or > not, but that's easy enough to figure out: > > >>> URLError > > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > NameError: name 'URLError' is not defined>>> import urllib2 > >>> urllib2.URLError > > <class 'urllib2.URLError'> > > So, that means you want something like: > > #!/usr/bin/env python > > import urllib2 > > url = "http://whatever...."; > try: > urllib2.urlopen(url) > print "url exists" > except urllib2.URLError: > print "url does not exist"
thanks a lot, this works like a charm jean -- http://mail.python.org/mailman/listinfo/python-list
