Paul
Im impressed again. Thank you so much
I had only a rough idea and you are realy effective in SAGE (too).
This time I have no additional concrete questions
but I'm strongly interested  in your general opinion
concerning the comparison MAPLE-SAGE (any links?)
Andrzej Chrzeszczyk

On 11 Sty, 23:09, Paul Zimmermann <[EMAIL PROTECTED]> wrote:
>        Dear Andrzej,
>
> > I don't know if elegant Paul Zimmermann's MAPLE solution
> > has  counterpart in SAGE (I'm affraid it hasn't)  but his remark on
> > the Groebner bases (SINGULAR, MACAULAY2 interf?) may be essentiall.
> > Does the discussion mean that I have to use the closed source
> > software?
> > Still waiting for reply.
>
> I was able to do the job with SAGE, but I have to confess it was not as easy
> as in Maple (however I am still more fluent in Maple):
>
> ----------------------------------------------------------------------
> | SAGE Version 2.9.3, Release Date: 2008-01-05                       |
> | Type notebook() for the GUI, and license() for information.        |
> ----------------------------------------------------------------------
> sage: var('x1,y1,x2,y2,x3,y3,a,b')
> sage: eq1 = y1^2 -(x1^3+a*x1+b)
> sage: eq2 = y2^2 -(x2^3+a*x2+b)
> sage: eq3 = y3^2 -(x3^3+a*x3+b)
> sage: lambda12 = (y1 - y2)/(x1 - x2)
> sage: x4       = (lambda12*lambda12 - x1 - x2)
> sage: nu12     = (y1 - lambda12*x1)
> sage: y4       = (-lambda12*x4 - nu12)
> sage: lambda23 = ((y2 - y3)/(x2 - x3))
> sage: x5       = (lambda23*lambda23 - x2 - x3)
> sage: nu23     = (y2 - lambda23*x2)
> sage: y5       = (-lambda23*x5 - nu23)
> sage: s1 =(x1 - x5)*(x1 - x5)*((y3 - y4)*(y3-y4) - (x3+x4)*(x3-x4)*(x3-x4))
> sage: s2 =(x3 - x4)*(x3 - x4)*((y1 - y5)*(y1-y5) - (x1+x5)*(x1-x5)*(x1-x5))
> sage: n12 = numerator(factor(s1-s2))
> sage: R = singular.ring(0, '(a,b,x1,x2,x3,y1,y2,y3)')
> sage: I = singular.ideal([repr(eq1), repr(eq2), repr(eq3)])
> sage: I2 = I.groebner()
> sage: singular.reduce(repr(n12), I2)
>
> 0
>
> In particular:
>
> (1) is there a better way to normalize a rational expression that calling
>     factor? Apparently numerator alone does not do the job.
> (2) can we get rid of the repr() calls?
>
> Paul Zimmermann
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