Yooooooooo !!

> Yes indeed -- with a formula like that, there's little reason not to
> implement it ad-hoc every time.  Unless a user wants it, and doesn't
> know this bit of information.  Though... what Nathannnnnn said was
> that he wants to know which bit changes...
>
> (i.valuation(2) for i in srange(1,2^n))
>
> does the job -- though this can certainly be implemented better.

Well, it's true that the one-liner simplifies a lot of things :-D

There are good implementations there if we need them in some fast C
code though : www.jjj.de/fxt/fxtbook.pdf

But my problem is solved ! Thanks :-D

Nathann

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