On Thu, Dec 5, 2013 at 9:50 PM, Nils Bruin <nbr...@sfu.ca> wrote:

> It will be very hard to beat the simple closed formula
>
> ( (i>>1) ^^ i for i in xrange(2^n) )
>

Yes indeed -- with a formula like that, there's little reason not to
implement it ad-hoc every time.  Unless a user wants it, and doesn't
know this bit of information.  Though... what Nathannnnnn said was
that he wants to know which bit changes...

(i.valuation(2) for i in srange(1,2^n))

does the job -- though this can certainly be implemented better.

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