If you only use (regexp-...) the return values are implicitly
printed by the module and the module uses (print ...).
Compare
(print "\n")
(display "\n")
See docs on
#%module-begin
for more
On Fri, 07 Jun 2013 17:04:38 +0200, Sanjeev K Sharma <throw...@gmail.com>
wrote:
sorry, I did that too quick
I'm getting something working doing this
(display (regexp-replace* ...
I'll have to figure out now why (regexp-replaces ...) doesn't give me
the same.
______
On Fri, Jun 07, 2013 at 10:58:06AM -0400, Sanjeev K Sharma wrote:
thanks for the quick response, I can't get newlines in the output
program:
#lang racket
(display "inpu#\nt-str#\ning#\n\n")
(printf"~a~a~n""printf""inpu#\nt-str#\ning\n")
(printf"~a~a~n""printf""inpu\nt-str\ning\n")
(regexp-replace* "\n" "inpu#\nt-str#\ning#\n " "\n<br>")
(regexp-replace* "\n" "inpu#\nt-str#\ning#\n " "\\n<br>")
(regexp-replace* "\n" "inpu#\nt-str#\ning#\n " "#\n<br>")
(regexp-replace* "#\n" "inpu#\nt-str#\ning#\n " "#\n<br>")
(regexp-replace* "#\n" "inpu#\nt-str#\ning#\n " "#\\n<br>")
(regexp-replace* "#\n" "inpu#\nt-str#\ning#\n " "#\\\n<br>")
____________
output:
Welcome to DrRacket, version 5.3.4 [3m].
Language: racket; memory limit: 10000 MB.
inpu#
t-str#
ing#
printfinpu#
t-str#
ing
printfinpu
t-str
ing
"inpu#\n<br>t-str#\n<br>ing#\n<br> "
"inpu#\nn<br>t-str#\nn<br>ing#\nn<br> "
"inpu##\n<br>t-str##\n<br>ing##\n<br> "
"inpu#\n<br>t-str#\n<br>ing#\n<br> "
"inpu##\nn<br>t-str##\nn<br>ing##\nn<br> "
"inpu##\n\n<br>t-str##\n\n<br>ing##\n\n<br> "
>
(just throwing random numbers of # and \\ in to see what I'm
misunderstanding)
On Fri, Jun 07, 2013 at 09:24:07AM -0400, Sean Kanaley wrote:
> (regexp-replace* "\n" input-string "\n<br>")
>
> would be the target expansion for those pairs.
>
> On 06/07/2013 08:57 AM, Sanjeev K Sharma wrote:
> >I have to clean up a bunch of source files that don't show properly
> >
> >I have a file from which I'm reading a bunch of regular expressions
to replace, things like this:
> >
> >(#px"(?i:%5C)""/")
> >
> >but included in the same file (full of from-to pairs) are a bunch of
straight string replacements, like this:
> >
> >("…""\\…")
> >
> >
> >I cannot figure out what's wrong with this one: what to do here
> >
> >("\n""\n<br>")
> >
> >it replaces the starting "\n" but never puts in the replacement "\n"
> >
> >I've doubled/tripled/quadrupled on the backslashes
> >
> >("\n""\\n<br>")
> >("\n""\\\n<br>")
> >
> >but that doesn't put in a newline, rather two separate characters,
"backslash" and "n"
> >
> >any hints what I'm doing wrong here?
> >____________________
> > Racket Users list:
> > http://lists.racket-lang.org/users
>
____________________
Racket Users list:
http://lists.racket-lang.org/users
--
---------------------------------------------------------
Tobias Hammer
DLR / Robotics and Mechatronics Center (RMC)
Muenchner Str. 20, D-82234 Wessling
Tel.: 08153/28-1487
Mail: tobias.ham...@dlr.de
____________________
Racket Users list:
http://lists.racket-lang.org/users
