(regexp-replace* "\n" input-string "\n<br>")
would be the target expansion for those pairs. On 06/07/2013 08:57 AM, Sanjeev K Sharma wrote:
I have to clean up a bunch of source files that don't show properly I have a file from which I'm reading a bunch of regular expressions to replace, things like this: (#px"(?i:%5C)""/") but included in the same file (full of from-to pairs) are a bunch of straight string replacements, like this: ("…""\\…") I cannot figure out what's wrong with this one: what to do here ("\n""\n<br>") it replaces the starting "\n" but never puts in the replacement "\n" I've doubled/tripled/quadrupled on the backslashes ("\n""\\n<br>") ("\n""\\\n<br>") but that doesn't put in a newline, rather two separate characters, "backslash" and "n" any hints what I'm doing wrong here? ____________________ Racket Users list: http://lists.racket-lang.org/users
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