sorry, I did that too quick
I'm getting something working doing this
(display (regexp-replace* ...
I'll have to figure out now why (regexp-replaces ...) doesn't give me the same.
______
On Fri, Jun 07, 2013 at 10:58:06AM -0400, Sanjeev K Sharma wrote:
> thanks for the quick response, I can't get newlines in the output
>
> program:
> #lang racket
> (display "inpu#\nt-str#\ning#\n\n")
> (printf"~a~a~n""printf""inpu#\nt-str#\ning\n")
> (printf"~a~a~n""printf""inpu\nt-str\ning\n")
> (regexp-replace* "\n" "inpu#\nt-str#\ning#\n " "\n<br>")
> (regexp-replace* "\n" "inpu#\nt-str#\ning#\n " "\\n<br>")
> (regexp-replace* "\n" "inpu#\nt-str#\ning#\n " "#\n<br>")
> (regexp-replace* "#\n" "inpu#\nt-str#\ning#\n " "#\n<br>")
> (regexp-replace* "#\n" "inpu#\nt-str#\ning#\n " "#\\n<br>")
> (regexp-replace* "#\n" "inpu#\nt-str#\ning#\n " "#\\\n<br>")
>
> ____________
> output:
> Welcome to DrRacket, version 5.3.4 [3m].
> Language: racket; memory limit: 10000 MB.
> inpu#
> t-str#
> ing#
>
> printfinpu#
> t-str#
> ing
>
> printfinpu
> t-str
> ing
>
> "inpu#\n<br>t-str#\n<br>ing#\n<br> "
> "inpu#\nn<br>t-str#\nn<br>ing#\nn<br> "
> "inpu##\n<br>t-str##\n<br>ing##\n<br> "
> "inpu#\n<br>t-str#\n<br>ing#\n<br> "
> "inpu##\nn<br>t-str##\nn<br>ing##\nn<br> "
> "inpu##\n\n<br>t-str##\n\n<br>ing##\n\n<br> "
> >
>
> (just throwing random numbers of # and \\ in to see what I'm
> misunderstanding)
>
> On Fri, Jun 07, 2013 at 09:24:07AM -0400, Sean Kanaley wrote:
> > (regexp-replace* "\n" input-string "\n<br>")
> >
> > would be the target expansion for those pairs.
> >
> > On 06/07/2013 08:57 AM, Sanjeev K Sharma wrote:
> > >I have to clean up a bunch of source files that don't show properly
> > >
> > >I have a file from which I'm reading a bunch of regular expressions to
> > >replace, things like this:
> > >
> > >(#px"(?i:%5C)""/")
> > >
> > >but included in the same file (full of from-to pairs) are a bunch of
> > >straight string replacements, like this:
> > >
> > >("…""\\…")
> > >
> > >
> > >I cannot figure out what's wrong with this one: what to do here
> > >
> > >("\n""\n<br>")
> > >
> > >it replaces the starting "\n" but never puts in the replacement "\n"
> > >
> > >I've doubled/tripled/quadrupled on the backslashes
> > >
> > >("\n""\\n<br>")
> > >("\n""\\\n<br>")
> > >
> > >but that doesn't put in a newline, rather two separate characters,
> > >"backslash" and "n"
> > >
> > >any hints what I'm doing wrong here?
> > >____________________
> > > Racket Users list:
> > > http://lists.racket-lang.org/users
> >
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