Thanks to both of you. I'll change it to a single vector.
On Jul 29, 2012, at 3:07 PM, Matthias Felleisen <matth...@ccs.neu.edu> wrote: > > For 81 slots, I'd actually use a (define b (make-vector 81 0)) instead and > use an access polynomial. I am almost certain that it is faster. > > > > > On Jul 29, 2012, at 6:00 PM, Eli Barzilay wrote: > >> Yesterday, Gregory Woodhouse wrote: >>> (define b(make-vector 9 (make-vector 9 0))) >> >> BTW, this is wrong -- it builds a vector of 9 zeros, then uses that >> same vector 9 times: >> >> -> (define x (make-vector 2 (make-vector 2 0))) >> -> x >> '#(#(0 0) #(0 0)) >> -> (vector-set! (vector-ref x 0) 0 1) >> -> x >> '#(#(1 0) #(1 0)) >> -> (print-graph #t) >> -> x >> '#(#0=#(1 0) #0#) >> >> -- >> ((lambda (x) (x x)) (lambda (x) (x x))) Eli Barzilay: >> http://barzilay.org/ Maze is Life! >> ____________________ >> Racket Users list: >> http://lists.racket-lang.org/users > ____________________ Racket Users list: http://lists.racket-lang.org/users
