For 81 slots, I'd actually use a (define b (make-vector 81 0)) instead and use an access polynomial. I am almost certain that it is faster.
On Jul 29, 2012, at 6:00 PM, Eli Barzilay wrote: > Yesterday, Gregory Woodhouse wrote: >> (define b(make-vector 9 (make-vector 9 0))) > > BTW, this is wrong -- it builds a vector of 9 zeros, then uses that > same vector 9 times: > > -> (define x (make-vector 2 (make-vector 2 0))) > -> x > '#(#(0 0) #(0 0)) > -> (vector-set! (vector-ref x 0) 0 1) > -> x > '#(#(1 0) #(1 0)) > -> (print-graph #t) > -> x > '#(#0=#(1 0) #0#) > > -- > ((lambda (x) (x x)) (lambda (x) (x x))) Eli Barzilay: > http://barzilay.org/ Maze is Life! > ____________________ > Racket Users list: > http://lists.racket-lang.org/users ____________________ Racket Users list: http://lists.racket-lang.org/users
