Dear Duncan,
Duncan Murdoch wrote on 2020-09-29 11:57:
On 29/09/2020 5:37 a.m., Helmut Schütz wrote:
Here I'm lost. power.TOST(theta0, CV, ...) vectorizes properly for
theta0 _or_ CV but no _both_. Hence
library(PowerTOST)
power.TOST(theta0 = c(0.9, 0.95, 1), CV = 0.25, n = 28)
and
power.TOST(theta0 = 0.95, CV = c(0.2, 0.25, 0.3), n = 28)
work, whereas
power.TOST(theta0 = c(0.9, 0.95, 1), 0.95, CV = c(0.2, 0.25, 0.3), n
= 28)
not. Of note, we will throw an error in the next release if both
arguments are vectors.
I wouldn't do that, because it doesn't fit the usual R style. It's
very common for functions to allow vector inputs in several arguments,
and match up corresponding values to form a vector result.
I see. Here it would require to give the result as a matrix,
data.frame,... Substantial change in the code though doable.
If you want to use Vectorize, the command would be
power.TOST.vectorized <- Vectorize(power.TOST, c("theta0", "CV"))
library(PowerTOST)
theta0 <- unique(sort(c(0.95, seq(0.95*0.95, 1, length.out = 10))))
CV <- unique(sort(c(0.25, seq(0.25*0.8, 0.25*1.2, length.out = 10))))
power.TOST.vectorized <- Vectorize(power.TOST, c("theta0", "CV", "n"))
and
power.TOST.vectorized(theta0 = theta0, CV = CV, n = 28)
gives the diagonal elements of the desired 11*11 matrix:
z <- matrix(ncol = length(theta0), nrow = length(CV))
for (i in seq_along(CV)) {
z[i, ] <- power.TOST(theta0 = theta0, CV = CV[i], n = 28)
}
Helmut
--
Ing. Helmut Schütz
BEBAC – Consultancy Services for
Bioequivalence and Bioavailability Studies
Neubaugasse 36/11
1070 Vienna, Austria
E helmut.schu...@bebac.at
W https://bebac.at/
F https://forum.bebac.at/
______________________________________________
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
