HI,
I don't understand why you're using lapply.
Please provide a example of your 'x' data.frame
str(x)
On 27/03/2008, Paul Lemmens <[EMAIL PROTECTED]> wrote:
> Hi Henrique,
>
>
> On Thu, Mar 27, 2008 at 2:52 PM, Henrique Dallazuanna <[EMAIL PROTECTED]>
> wrote:
> > Try this:
> >
> > foo <- function(x)
> > {
> > clipname <- "LK"
> > out <- list()
> > out[[clipname]] <- rnorm(5)
> > return(out)
> > }
>
> That easy ... Hadn't thought of it. But now I have a refinement in foo()
>
> foo <- function(x) {
> out <- list()
> lapply(x$clipno, function(c) {
> clipname <- x$clipname
> # stuff
>
> out[[clipname]] <- rnorm(5)
> })
> return(out)
> }
>
>
> But this returns the/an empty list?
>
>
> Best regards,
>
> Paul Lemmens
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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