Hi Henrique, On Thu, Mar 27, 2008 at 2:52 PM, Henrique Dallazuanna <[EMAIL PROTECTED]> wrote: > Try this: > > foo <- function(x) > { > clipname <- "LK" > out <- list() > out[[clipname]] <- rnorm(5) > return(out) > } That easy ... Hadn't thought of it. But now I have a refinement in foo()
foo <- function(x) { out <- list() lapply(x$clipno, function(c) { clipname <- x$clipname # stuff out[[clipname]] <- rnorm(5) }) return(out) } But this returns the/an empty list? Best regards, Paul Lemmens ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.