Try this:
foo <- function(x)
{
clipname <- "LK"
out <- list()
out[[clipname]] <- rnorm(5)
return(out)
}
On 27/03/2008, Paul Lemmens <[EMAIL PROTECTED]> wrote:
> Dear all,
>
> I have a piece of code along the lines of
>
> f <- function(x) {
> clipname <- "LK" # but is in real determined based on info in data.frame x
> # other manipulations
> return( list(clipname=list(....)))
> }
>
> My intention is to do
>
> out <- f(dat)
>
> and then (in this example) having/getting
>
> out$LK
>
> which is a list in itself.
>
>
> Of course, it doesn't work like this, but having tried all kinds of
> combinations of eval(), parse(), substitute(), and friends I was
> unable to get the contents of clipname as the element name of the list
> that I return in f().
>
> Is this possible to do so at all and if so, what am I missing?
>
>
> Kind regards,
> Paul Lemmens
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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