Here is a start > x <- as.data.frame(runif(2000, 12, 38)) > length(x) [1] 1 > names(x) [1] "runif(2000, 12, 38)" >
Why are you turning x and y into data frames? It also looks as if you should be using if(...) ... else ... rather than ifelse(.,.,), too. You need to sort out a few issues, it seems. -----Original Message----- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of eric Sent: Thursday, 3 March 2011 1:19 PM To: r-help@r-project.org Subject: [R] What am I doing wrong with this loop ? What is wrong with this loop ? I am getting an error saying incorrect number of dimensions y[i,2] x <- as.data.frame(runif(2000, 12, 38)) z <-numeric(length(x)) y <- as.data.frame(z) for(i in 1:length(x)) { y <- ifelse(i < 500, as.data.frame(lowess(x[1:i,1], f=1/9)) , as.data.frame(lowess(x[(i-499):i,1], f=1/9))) z[i] <-y[i,2] } -- View this message in context: http://r.789695.n4.nabble.com/What-am-I-doing-wrong-with-this-loop-tp3332703p3332703.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
