From: Wanlong Gao <gaowanl...@cn.fujitsu.com>
If the total number of the assigned numa nodes memory is not
equal to the assigned ram size, it will write the wrong data
to ACPI talb, then the guest will ignore the wrong ACPI table
and recognize all memory to one node. It's buggy, we should
check it to ensure that we write the right data to ACPI table.
Signed-off-by: Wanlong Gao <gaowanl...@cn.fujitsu.com>
Reviewed-by: Eduardo Habkost <ehabk...@redhat.com>
Signed-off-by: Paolo Bonzini <pbonz...@redhat.com>
---
numa.c | 11 +++++++++++
1 file changed, 11 insertions(+)
diff --git a/numa.c b/numa.c
index 395c14f..8ba66f1 100644
--- a/numa.c
+++ b/numa.c
@@ -127,6 +127,7 @@ void numa_add(const char *optarg)
void set_numa_nodes(void)
{
if (nb_numa_nodes > 0) {
+ uint64_t numa_total;
int i;
if (nb_numa_nodes > MAX_NODES) {
@@ -154,6 +155,16 @@ void set_numa_nodes(void)
node_mem[i] = ram_size - usedmem;
}
+ numa_total = 0;
+ for (i = 0; i < nb_numa_nodes; i++) {
+ numa_total += node_mem[i];
+ }
+ if (numa_total != ram_size) {
+ fprintf(stderr, "qemu: numa nodes total memory size "
+ "should equal to ram_size\n");
+ exit(1);
+ }
+
for (i = 0; i < nb_numa_nodes; i++) {
if (!bitmap_empty(node_cpumask[i], MAX_CPUMASK_BITS)) {
break;
--
1.8.5.3
