On 23 Jan 2006 07:18:13 -0800, Pankaj <[EMAIL PROTECTED]> wrote:
>
> [snip]
>What i tried in python was::
>
>f = open( "./1.c", "r")
>fNew = open( "./1_new.c", "w")
>for l in f:
> print l
> lineno = lineno + 1
> strToFind = "for\((.*)\;(.*)"
>
> ## For Converting int to string, i.e. line no. to string
> lineNoClone = lineno
>
> pattern = "printf(\"" + str( lineNoClone) + "\"),"
>
> print pattern
>
> strToReplace = "for\(" + pattern + "\1\;"
>
> fNew.write( l.replace( strToFind, strToReplace) )
>
> print l
>
>fNew.close()
>
str.replace() does not support regular expressions. Take a look at the re
module.
Jean-Paul
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