Pankaj wrote: > Here problem is , i am not getting backreferences using \1 and \2 >
You wrote: > subStrPattern1_hasInitialization = "\1" "\1" is the way to create a string containing a control-A character. What you actually wanted was a string containing a backslash and a "1", so you need either: "\\1" or r"\1" Try using the print statement to see what all those strings you are creating actually contain. -- http://mail.python.org/mailman/listinfo/python-list