Pankaj wrote:
>>>> Perl :::
> ***********
> while( <FILEHANDLE> )
> {
>
> line = $_;
>
> pattern = "printf\( \"$lineNo \" \),";
>
> line =~ s/"for(.*)\((*.)\;(.*)/for$1\($pattern$2\;$3/g;
> }
>
> This is used to
>
> search for : for ( i = 0; i < 10; i++)
> Replace with: for( printf( "10" ), i =0; i < 10; i++)
> Where 10 is the line no.
import re
import fileinput
for L in fileinput.input(inplace=True):
pattern = 'printf("%d"),' % input.filelineno()
L = re.sub(r"for(.*)\((*.)\;(.*)", r"for\1\(%s\2;\3" % pattern, L)
print L,
or something
--
Giovanni Bajo
--
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