Mathijs wrote: > Python beginner here and very much enjoying it. I'm looking for a > pythonic way to find how many listmembers are also present in a reference > list. Don't count duplicates (eg. if you already found a matching member > in the ref list, you can't use the ref member anymore). > > Example1: > ref=[2, 2, 4, 1, 1] > list=[2, 3, 4, 5, 3] > solution: 2 > > Example2: > ref=[2, 2, 4, 1, 1] > list=[2, 2, 5, 2, 4] > solution: 3 (note that only the first two 2's count, the third 2 in the > list should not be counted) > > Any suggestions or comments? sum(min(list.count(n), ref.count(n)) for n in set(ref))
Is that it? Peter -- http://mail.python.org/mailman/listinfo/python-list
