On 23/01/2006 18:41, Mathijs uttered: >> len([ref.pop(ref.index(x)) for x in lis if x in ref])
> This is the type of solution I was hoping to see: one-liners, with no > use of local variables. As Tim Chase already wrote, it has only one > less elegant side: it alters the original ref list. > > Thanks for your suggestion. May I suggest another one-liner: len(set(ref).intersection(lis)) I have no idea how this scales/performs compared to the other suggestions you've received, but I find it immediately comprehensible. -- Morten -- http://mail.python.org/mailman/listinfo/python-list
