On Mon, 23 Jan 2006 17:41:55 +0000, Mathijs wrote: > Op 19 jan 2006 vond "[EMAIL PROTECTED]" : > >> another approach: >> >> ref = [2,2,4,1,1] >> lis = [2,2,5,2,4] >> >> len([ref.pop(ref.index(x)) for x in lis if x in ref]) >> > > This is the type of solution I was hoping to see: one-liners, with no use > of local variables.
Because you like unreadable, incomprehensible, unmaintainable code? *wink* -- Steven. -- http://mail.python.org/mailman/listinfo/python-list
