On Sat, Oct 25, 2014 at 12:46 AM, Larry Hudson <org...@yahoo.com.dmarc.invalid> wrote: >> name="123-xyz-abc" >> for x in name: >> if x in range(10): > > x is a character (a one-element string). range(10) is a list of ints. A > string will never match an int. BTW, as it is used here, range(10) is for > Py2, for Py3 it needs to be list(range(10)).
The last comment is incorrect. You can do membership tests on a Python 3 range object: >>> range(2, 4) range(2, 4) >>> for i in range(5): ... print(i, i in range(2, 4)) ... 0 False 1 False 2 True 3 True 4 False You can also index them: >>> range(50, 100)[37] 87 slice them: >>> range(0, 100, 2)[:25] range(0, 50, 2) get their length: >>> len(range(25, 75)) 50 search them: >>> range(25, 75).index(45) 20 and generally do most operations that you would expect to be able to do with an immutable sequence type, with the exceptions of concatenation and multiplication. And as I observed elsewhere in the thread, such operations are often more efficient on range objects than by constructing and operating on the equivalent lists. -- https://mail.python.org/mailman/listinfo/python-list
