On Fri, 24 Oct 2014 11:57:12 -0700 (PDT), sohcahto...@gmail.com wrote: >On Friday, October 24, 2014 11:17:53 AM UTC-7, Seymore4Head wrote: >> On Fri, 24 Oct 2014 11:52:15 -0600, Ian Kelly <ian.g.ke...@gmail.com> >> wrote: >> >> >On Fri, Oct 24, 2014 at 11:03 AM, Seymore4Head >> ><Seymore4Head@hotmail.invalid> wrote: >> >> Actually I was a little frustrated when I added that line back in as >> >> the other lines all work. >> >> Using list(range(10)) Doesn't throw an error but it doesn't work. >> >> >> >> http://i.imgur.com/DTc5zoL.jpg >> >> >> >> The interpreter. I don't know how to use that either. >> > >> >Try both of these in the interpreter, and observe the difference: >> > >> >7 in range(10) >> > >> >"7" in range(10) >> > >> >Do you understand what the difference between 7 and "7" is? >> >> I do understand that. 7 is a number and "7" is a string. >> What my question was...and still is...is why >> Python 3 fails when I try using >> y=1 800 get charter >> >> y in range str(range(10)) >> should work because y is a string and str(range(10)) should be >> "y" in str(1) fails. >> It doesn't give an error it's just not True when y is a number. >> >> These hints are just not working. I am too thick for hints. :) >> If you could use it in the code, I might understand. >> The other work arounds that were posted work. >> I have used them. str(range(10)) doesn't work. >> >> import string >> def nametonumber(name): >> lst=[] >> nx=[] >> digit=[] >> digit="".join(str(i) for i in range(10)) >> for x in name: >> lst.append(x) >> for y in (lst): >> if y in list(range(1,10)): >> #if y in "1234567890": >> #if y.isdigit(): >> #if y in digit: >> #if y in string.digits: >> nx.append(y) >> if y in " -()": >> nx.append(y) >> if y in "abc": >> nx.append("2") >> if y in "def": >> nx.append("3") >> if y in "ghi": >> nx.append("4") >> if y in "jkl": >> nx.append("5") >> if y in "mno": >> nx.append("6") >> if y in "pqrs": >> nx.append("7") >> if y in "tuv": >> nx.append("8") >> if y in "wxyz": >> nx.append("9") >> number="".join(e for e in nx) >> return number >> a="1-800-getcharter" >> print (nametonumber(a))#1800 438 2427 837 >> a="1-800-leo laporte" >> print (nametonumber(a)) >> a="1 800 dialaho" >> print (nametonumber(a)) >> >> Please > >Your code here is actually pretty close to a correct answer. Just a few >things to consider... > >- Why are you converting your name string to a list? It is unnecessary. When >you do "for y in <some string>", then y will still be single characters on >each iteration of the loop. > >- "if y in string.digits" should work fine. > >- "if y in list(range(1,10)" won't work for two reasons: First, it creates a >list of numbers, not strings. Second, even if it did, it would be missing the >"0" digit. > >- At the end, when you convert your list to a string, you don't need to use >list comprehension, since nx is already a list. number = "".join(nx) should >work fine. > >Also, in general, you need to stop and slow down and think like a programmer. >If you get an error, your instinct shouldn't be to just hack at it to make the >error go away. Look at the error and try to make sense of it. Learn what the >error means and try to fix the core problem. > >And for @#$%'s sake...stop saying "It isn't working" and not elaborating. >You've been told by every other post in this thread to show us what you did >and what the error was. You've also been told to *NOT* retype what you see >and to copy/paste your code and the error because when you make a typo when >copying, we might see a problem that doesn't exist and then you just get more >confused.
Ok I think I may have the question you guys are looking for. I just posted it. See above. But it's still broke. :( -- https://mail.python.org/mailman/listinfo/python-list
