On Fri, 24 Oct 2014 14:15:13 -0400, Seymore4Head wrote: > I do understand that. 7 is a number and "7" is a string. > What my question was...and still is...is why Python 3 fails when I try > using y=1 800 get charter > > y in range str(range(10)) > should work because y is a string and str(range(10)) should be "y" in > str(1) fails. > It doesn't give an error it's just not True when y is a number.
This is because str(range(10)) does not do what you think it does. In python 2.x, str(range(10)) creates a string representation of the complete list, not a list of the string representation of the separate list elements. '[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]' In python 3.x, str(range(10)) creates a string representation of the list object. 'range(0, 10)' the only single digit strings in the python3 representation are "0" and "1" To recreate the python2 behaviour in python 3, use: str(list(range(10))) which gives '[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]' howver the test: if x.isdigit(): is much better. But finally, with your telephone number decoder, look at: http://www.codeskulptor.org/#user38_QnR06Upp4AH6h0Q.py -- Denis McMahon, denismfmcma...@gmail.com -- https://mail.python.org/mailman/listinfo/python-list
