Re: I am out of trial and error again Lists

[Mark Lawrence]

On 22/10/2014 21:30, Seymore4Head wrote:
def nametonumber(name):
     lst=[""]
     for x,y in enumerate (name):
         lst=lst.append(y)
     print (lst)
     return (lst)
a=["1-800-getcharter"]
print (nametonumber(a))#18004382427837

The syntax for when to use a () and when to use [] still throws me a
curve.

For now, I am trying to end up with a list that has each character in
"a" as a single item.

I get:
None
None


Following on from the numerous responses you've had here, I've no idea 
if this helps your thought processes but there's only one way for you to 
find out http://www.greenteapress.com/thinkpython/ :)

--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.

Mark Lawrence

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