On Fri, 24 Oct 2014 19:48:16 -0400, Seymore4Head
<Seymore4Head@Hotmail.invalid> wrote:
>On Fri, 24 Oct 2014 16:27:58 -0700 (PDT), Rustom Mody
><rustompm...@gmail.com> wrote:
>
>>On Saturday, October 25, 2014 4:30:47 AM UTC+5:30, Seymore4Head wrote:
>>> On Wed, 22 Oct 2014 16:30:37 -0400, Seymore4Head wrote:
>>>
>>> name="123-xyz-abc"
>>> a=range(10)
>>> b=list(range(10))
>>> c=str(list(range(10)))
>>> print ("a",(a))
>>> print ("b",(b))
>>> print ("c",(c))
>>>
>>> for x in name:
>>> if x in a:
>>> print ("a",(x))
>>> if x in b:
>>> print ("b",(x))
>>> if x in c:
>>> print ("c",(x))
>>>
>>> B is type list and C is type str.
>>> I guess I am still a little too thick. I would expect b and c to
>>> work.
>>
>>Lets simplify the problem a bit.
>>Do all the following in interpreter window
>>
>>>>> name="012"
>>>>> b=list(range(3))
>>
>>>>> for x in name: print x
>>
>>>>> for x in b: print x
>>
>>Same or different?
>>
>>Now go back to Denis' nice example and put in type(x)
>>into each print
>>
>>Same or different?
>
>First. The interpreter is not good for me to use even when I am using
>Python 3 because I forget to add : and I forget to put () around the
>print statements.
>
>To keep me from having to correct myself every time I use it, it is
>just easier to make a short py file.
>
>Here is mine:
>
>name="012"
>b=list(range(3))
>for x in name: print (x)
>print (type (x))
>for x in b: print (x)
>print (type (b))
>
>I don't understand what I was supposed to learn from that. I know
>that name will be a string so x will be a string.
>I would still think if you compare a 1 from a string to a 1 from a
>list, it should be the same.
>
>Obviously I am wrong, but we knew that already.
>I get they are not the same, but I still think they should be.
>
>name="012"
>b=list(range(3))
>print (name[1])
>print ([1])
>
>1
>[1]
>
>OK I get it. They are not the same. I was expecting "1"
>
Wait! I don't get it.
name="012"
b=list(range(3))
print (name[1])
print (b[1])
1
1
I forgot the b
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