In article <mailman.1976.1349747963.27098.python-l...@python.org>,
Terry Reedy <tjre...@udel.edu> wrote:
> On 10/8/2012 3:28 PM, mooremath...@gmail.com wrote:
> > What's the best way to accomplish this? Am I over-complicating it? My gut
> > feeling is there is a better way than the following:
> >
> >>>> import itertools
> >>>> x = [1, 2, 3]
> >>>> y = list(itertools.chain.from_iterable(('insertme', x[i]) for i in
> >>>> range(len(x))))
> >>>> y
> > ['insertme', 1, 'insertme', 2, 'insertme', 3]
>
> The straightforward, crystal-clear, old-fashioned way
>
> >>> lst = []
> >>> for item in [1,2,3]:
> lst.append('insert me')
> lst.append(item)
I'm going to go with this one. I think people tend to over-abuse list
comprehensions. They're a great shorthand for many of the most common
use cases, but once you stray from the simple examples, you quickly end
up with something totally obscure.
> y = list(itertools.chain.from_iterable(('insertme', x[i]) for i in
> range(len(x))))
A statement ending in four close parens is usually going to be pretty
difficult to figure out. This is one where I had to pull out my pencil
and start pairing them off manually to figure out how to parse it.
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