On 2012-10-08 20:28, mooremath...@gmail.com wrote:
What's the best way to accomplish this? Am I over-complicating it? My gut
feeling is there is a better way than the following:
import itertools
x = [1, 2, 3]
y = list(itertools.chain.from_iterable(('insertme', x[i]) for i in
range(len(x))))
y
['insertme', 1, 'insertme', 2, 'insertme', 3]
I appreciate any and all feedback.
Slightly better is:
y = list(itertools.chain.from_iterable(('insertme', i) for i in x))
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