On 8 October 2012 20:28, <mooremath...@gmail.com> wrote:
> What's the best way to accomplish this? Am I over-complicating it? My
> gut feeling is there is a better way than the following:
>
> >>> import itertools
> >>> x = [1, 2, 3]
> >>> y = list(itertools.chain.from_iterable(('insertme', x[i]) for i in
> range(len(x))))
> >>> y
> ['insertme', 1, 'insertme', 2, 'insertme', 3]
>
> I appreciate any and all feedback.
>
That's probably not the best way.
list(itertools.chain.from_iterable(zip(itertools.repeat("insertme"), [1, 2,
> 3])))
(tested)
written like this:
inserts = itertools.repeat("insertme")
itertools.chain.from_iterable(zip(inserts, x))
(untested)
But it's not far. I wouldn't use Ian Kelly's method (no offence), because
of len(x): it's less compatible with iterables. Others have ninja'd me with
good comments, too.
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