On Fri, Jun 8, 2012 at 10:43 AM, Emile van Sebille <em...@fenx.com> wrote:
> Or alternately by leveraging true/false as 1/0:
>
>>>> [ 100*(not(ii%2))+ii for ii in range(10)]

The same thing, leaving bools out of it altogether:

>>> [100*(1-ii%2)+ii for ii in range(10)]
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