>From a sequence of numbers, I'm trying to get a list that does something to >even numbers but leaves untouched the odd ones, say:
[0,1,2,3,4,...] ==> [100,1,102,3,104,...] I know that this can be done with an auxiliary function, as follows: ->>> def filter(n): ... if (n%2 == 0): ... return 100+n ... return n ... ->>> L = range(10) ->>> [filter(n) for n in L] [100, 1, 102, 3, 104, 5, 106, 7, 108, 9] I wonder whether there can be a single list comprehension expression to get this result without the aid of the auxiliary function. Do you have any comments on this? Thanks, --Sergio. -- http://mail.python.org/mailman/listinfo/python-list
