On Fri, Jun 8, 2012 at 6:10 PM, Julio Sergio <julioser...@gmail.com> wrote: > >From a sequence of numbers, I'm trying to get a list that does something to > >even > numbers but leaves untouched the odd ones, say: > > [0,1,2,3,4,...] ==> [100,1,102,3,104,...] > > I know that this can be done with an auxiliary function, as follows: > > ->>> def filter(n): > ... if (n%2 == 0): > ... return 100+n > ... return n > ... > ->>> L = range(10) > ->>> [filter(n) for n in L] > [100, 1, 102, 3, 104, 5, 106, 7, 108, 9] > > I wonder whether there can be a single list comprehension expression to get > this > result without the aid of the auxiliary function. > > Do you have any comments on this?
>>> l = [0,1,2,3,4,5,6,7,8,9] >>> [n if n%2 else 100+n for n in l] [100, 1, 102, 3, 104, 5, 106, 7, 108, 9] Daniel -- http://mail.python.org/mailman/listinfo/python-list
