* Nikhil Verma <varma.nikhi...@gmail.com> [2012-03-26 08:49]:
> Hi
>
> I want something to achieve like this :-
>
> def random_number(id): # I am passing it from request
> # do something
> return random_number
>
> Output
>
> random_number(5)
> AXR670
>
> One input that is a number in return you are getting 6 digit alphanumeric
> string.
>
> I tried this
> s = '%06d' % random.randint(0, 999999)
>
> it gives : '192862' (a string )
>
> Thanks in advance.
ah - so I misunderstood - I thought you want a permutation of a given
6-digit number
It's still not quite clear to me what role 'id' is playing ... so let's
check this one;
and Steven, who is maybe more experienced than I am will help us ufrther
>>> import random, string
>>> def random_number(id):
... characters = list(string.ascii_lowercase +
... string.ascii_uppercase +
... string.digits)
... coll_rand = []
... for i in range(6):
... random.shuffle(characters)
... coll_rand.append(characters[0])
... return ''.join(coll_rand)
...
>>> id = 5
>>> print (random_number(id))
puMHCr
>>>
regards
Michael
>
> On Mon, Mar 26, 2012 at 12:10 PM, Michael Poeltl <
> michael.poe...@univie.ac.at> wrote:
>
> > * Nikhil Verma <varma.nikhi...@gmail.com> [2012-03-26 08:09]:
> > > Hi All
> > >
> > > How can we generate a 6 digit random number from a given number ?
> > what about this?
> >
> > >>> given_number=123456
> > >>> def rand_given_number(x):
> > ... s = list(str(x))
> > ... random.shuffle(s)
> > ... return int(''.join(s))
> > ...
> > >>> print (rand_given_number(given_number))
> > 653421
> >
>
>
>
> --
> Regards
> Nikhil Verma
> +91-958-273-3156
--
Michael Poeltl
Computational Materials Physics voice: +43-1-4277-51409
Univ. Wien, Sensengasse 8/12 fax: +43-1-4277-9514 (or 9513)
A-1090 Wien, AUSTRIA cmp.mpi.univie.ac.at
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