On Mon, Mar 26, 2012 at 5:08 PM, Nikhil Verma <varma.nikhi...@gmail.com> wrote: > Hi All > > How can we generate a 6 digit random number from a given number ? > > eg:- > > def number_generator(id): > random.randint(id,999999) > > When i am using this it is sometimes giving me five digit and sometimes 6 . > I want to avoid encryption . Can i have alphanumeric 6 digit random number > from this .
The easiest two ways to guarantee six digits are: 1) Pad the number with leading zeroes: def number_generator(): return "%06d"%random.randint(0,999999) 2) Set a minimum and a maximum: def number_generator(): return random.randint(100000,999999) I don't know what your id there is, but the first argument to randint is the minimum value to return. Alphanumeric is quite different. To generate a six-character random alphanumeric string, one easy technique is to use base 36 conversion on a random integer. Hope that helps! Chris Angelico -- http://mail.python.org/mailman/listinfo/python-list
