If you want it as an int: random.randint(100000, 999999) Or as a string: s = '%06d' % random.randint(0, 999999)
On Mon, Mar 26, 2012 at 2:08 AM, Nikhil Verma <varma.nikhi...@gmail.com>wrote: > Hi All > > How can we generate a 6 digit random number from a given number ? > > eg:- > > def number_generator(id): > random.randint(id,999999) > > When i am using this it is sometimes giving me five digit and sometimes 6 > . I want to avoid encryption . Can i have alphanumeric 6 digit random > number from this . > > Thanks in advance > > -- > Regards > Nikhil Verma > +91-958-273-3156 > > > -- > http://mail.python.org/mailman/listinfo/python-list > >
-- http://mail.python.org/mailman/listinfo/python-list