On Fri, Jul 15, 2011 at 4:03 AM, Ellerbee, Edward <eeller...@bbandt.com> wrote: > for makenewlist in range(0,count): > sortlist.append(npalist.pop(0) + nxxlist.pop(0))
This can alternatively be done with map(): sortlist = map(lambda x,y: x+y, npalist, nxxlist) However, I'm not sure what your code is meant to do if the two lists have differing numbers of elements (if the two regexps turn up differing numbers of results). If you can assume that this won't happen, the simple map call will do the job. (It would have been a lot cleaner if Python exposed its operators as functions. In Pike, that lambda would simply be `+ (backtick-plus).) Chris Angelico -- http://mail.python.org/mailman/listinfo/python-list
