On Oct 10, 11:44 pm, Benjamin Kaplan <benjamin.kap...@case.edu> wrote: > On Sun, Oct 10, 2010 at 5:29 PM, tinauser <tinau...@libero.it> wrote: > > On Oct 10, 6:54 am, Lawrence D'Oliveiro <l...@geek- > > central.gen.new_zealand> wrote: > >> In message > >> <d38a6549-379b-4ece-b391-904e15412...@i21g2000yqg.googlegroups.com>, > > >> tinauser wrote: > >> > now,the file will be opened only if i give the full path, not if i > >> > give only the name of the file, although the folder is in the path. > >> > what am I missing? > > >> The fact that sys.path is not used for that. > > > ok,then could you tell me if there is a way to have the folder of the > > module where the "open" command is? > > this module is called from C, and user could install the python code > > folder (where both the module and the file are) where he wants. > > open uses the current working directory, which is available through > the os.getcwd() function in Python. > If you want to use a path relative to the current module, you can use > that module's __file__ attribute. > os.path.dirname(os.path.abspath(__file__)) > will give you the absolute path to the directory with the current module in > it. > > So if you want to open the foo.txt file in the same directory as the > module, you use > os.path.join(os.path.dirname(__file__), 'foo.txt') > > > thank you in advance > > -- > >http://mail.python.org/mailman/listinfo/python-list > >
thanks a lot! -- http://mail.python.org/mailman/listinfo/python-list
