Thanks guys. So far I had only come out with
f = [eval('lambda x: x+'+str(j)) for j in range(3)]
...which I hated because, as everybody knows, eval is evil :-)
Enzo
On May 26, 5:20 pm, Arnaud Delobelle <arno...@googlemail.com> wrote:
> "Diez B. Roggisch" <de...@nospam.web.de> writes:
>
> > You need to capture n into the closure of the lambda:
>
> > f = [lambda x, n=n: x+j for j in xrange(n)]
>
> You mean [lambda x, j=j: x+j for j in xrange(n)]
>
> Another way would be [(lambda j:lambda x: x+j)(j) for j in xrange(n)]
>
> Or more readably:
>
> def adder(n):
> return lambda x: x+n
>
> [adder(j) for j in xrange(n)]
>
> --
> Arnaud
--
http://mail.python.org/mailman/listinfo/python-list
