"Diez B. Roggisch" <de...@nospam.web.de> writes: > You need to capture n into the closure of the lambda: > > f = [lambda x, n=n: x+j for j in xrange(n)]
You mean [lambda x, j=j: x+j for j in xrange(n)]
Another way would be [(lambda j:lambda x: x+j)(j) for j in xrange(n)]
Or more readably:
def adder(n):
return lambda x: x+n
[adder(j) for j in xrange(n)]
--
Arnaud
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