Quoth Steven D'Aprano <ste...@remove.this.cybersource.com.au>: > On Sun, 01 Feb 2009 12:01:11 -0800, Stephen Hansen wrote: > > > <br><div class="gmail_quote"><blockquote class="gmail_quote" > > style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt > > 0.8ex; padding-left: 1ex;"><br> I'd like to know how to elegantly check > > a list for the membership of<br> any of its items to another list. > > Not caring for elegance, I would<br> use the following code:<br> > > </blockquote><div><br>That's one of the useful properties of > > sets:<br><br>>>> a = [1,2,3]<br>>>> b = > > [3,4,5,6]<br>>>> set(a) & > > set(b)<br>set([3])<br>>>> > > set(a).intersection(b)<br>set([3])<br> <br>That's two spellings of the > > same thing. As for testing: an empty set like an empty list will return > > false, so "if set(a) & set(b):" will be true or false based on if > > there's any commonalities between the two > > lists.<br><br>--Stephen</div></div><br> > > > Stephen, do you see the utter mess your posts look like to some others?
I don't even see Stephen Hansen's posts. My newsreader just shows the header and says "[HTML part not displayed]". --RDM -- http://mail.python.org/mailman/listinfo/python-list
