inkhorn schrieb: > Dear all, > > I'd like to know how to elegantly check a list for the membership of > any of its items to another list. Not caring for elegance, I would > use the following code: > > blah = [1,2,3] > yadda = [3,4,5,6] > > blah[0] or blah[1] or blah[2] in yadda > > Please tell me how to change the preceding code into something nicer > where I don't have to keep extending the line based on the length of > the first list.
You can and should use Python's set type for membership testing. >>> blah = set([1,2,3]) >>> yadda = set([3,4,5,6]) >>> blah.issubset(yadda) False >>> blah.difference(yadda) set([1, 2]) >>> blah.symmetric_difference(yadda) set([1, 2, 4, 5, 6]) Christian -- http://mail.python.org/mailman/listinfo/python-list
