eliben wrote:
... a prety good try ...
def parse_path(path):
"""..."""
By the way, the comment is fine. I am going for brevity here.
lst = []
while 1:
head, tail = os.path.split(path)
if tail == '':
if head != '': lst.insert(0, head)
break
else:
lst.insert(0, tail)
path = head
return lst
----------------------------------
Did I miss something and there is a way to do this standardly ?
Nope, the requirement is rare.
Is this function valid, or will there be cases that will confuse it ?
parse_path('/a/b/c//d/')
Try something like:
def parse_path(path):
'''...same comment...'''
head, tail = os.path.split(path)
result = []
if not tail:
if head == path:
return [head]
# Perhaps result = [''] here to an indicate ends-in-sep
head, tail = os.path.split(head)
while head and tail:
result.append(tail)
head, tail = os.path.split(head)
result.append(head or tail)
result.reverse()
return result
--Scott David Daniels
[EMAIL PROTECTED]
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