Hello,
os.path.split returns the head and tail of a path, but what if I want
to have all the components ? I could not find a portable way to do
this in the standard library, so I've concocted the following
function. It uses os.path.split to be portable, at the expense of
efficiency.
----------------------------------
def parse_path(path):
""" Parses a path to its components.
Example:
parse_path("C:\\Python25\\lib\\site-packages\
\zipextimporter.py")
Returns:
['C:\\', 'Python25', 'lib', 'site-packages',
'zipextimporter.py']
This function uses os.path.split in an attempt to be portable.
It costs in performance.
"""
lst = []
while 1:
head, tail = os.path.split(path)
if tail == '':
if head != '': lst.insert(0, head)
break
else:
lst.insert(0, tail)
path = head
return lst
----------------------------------
Did I miss something and there is a way to do this standardly ?
Is this function valid, or will there be cases that will confuse it ?
Thanks in advance
Eli
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